Difference between revisions of "CSC231 Homework 3 Solutions Fall 2012"
(Created page with "--~~~~ ---- =Problem #1= <code><pre> Julia B. Edwards 231a-aa September 20, 2012 hw3a.txt Initially creates: eax: 00000000 ebx: 12345678 ecx: 87654321 edx: ffffffff Sourc...") |
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<source lang="asm"> | <source lang="asm"> | ||
− | ;;; ; Julia B. Edwards | + | ;;; ; Julia B. Edwards |
;;; ; 231a-aa | ;;; ; 231a-aa | ||
− | ;;; ; hw3c.asm | + | ;;; ; hw3c.asm (edited by D. Thiebaut) |
;;; ; | ;;; ; | ||
;;; ; This program prints out the following: | ;;; ; This program prints out the following: |
Latest revision as of 09:11, 1 October 2012
--D. Thiebaut 10:10, 1 October 2012 (EDT)
Problem #1
Julia B. Edwards
231a-aa
September 20, 2012
hw3a.txt
Initially creates:
eax: 00000000
ebx: 12345678
ecx: 87654321
edx: ffffffff
Sources and Destinations:
1) bl = 78 --> al
2) ch = 43 --> ah
3) dh = ff --> dl
4) bl = 78 --> dh
5) cx = 4321 --> bx
6) 'a' = 61 --> ch
7) 'a'+32 = 'a' + 20 (20 in hex = 32 in decimal) = 81 --> cl
New values in the reigsters:
eax: 00004378 (altered by steps 1 and 2)
ebx: 12344321 (altered by step 5)
ecx: 87656181 (altered by steps 6 and 7)
edx: ffff78ff (altered by steps 3 and 4)
Problem #2
;;; hw3b.asm
;;; Naomi Long (edited by D. Thiebaut)
;;; 231a-ad
;;;
;;; This program copies a string into another string
;;; without modifying any other variable's contents.
;;; The new string is output sandwiched between two different
;;; variables to show the lack of side-effects.
;;;
;;; [231a-ad@grendel ~/hw3]$ ./hw3b
;;; CSC231 Assembly
;;;
;;; CSC231 Assembly
;;;
;;; Fall 2012
;;;
;;; [231a-ad@grendel ~/hw3]$
;;;
;;; To run:
;;; nasm -f elf -F stabs hw3b.asm
;;; ld -melf_i386 -o hw3b hw3b.o
;;; ./hw3b
section .data
msg1 db "CSC231 Assembly", 10, 10
msg1Len equ $-msg1
msg2 db "................", 10
msg2Len equ $-msg2
msg3 db "Fall 2012", 10, 10
msg3Len equ $-msg3
section .text
global _start
_start:
;;; move "CSC2" into msg2
mov eax, dword[msg1]
mov dword[msg2], eax
;;; move "31 A" into msg2
mov eax, dword[msg1+4]
mov dword[msg2+4], eax
;;; move "ssem" into msg2
mov eax, dword[msg1+8]
mov dword[msg2+8], eax
;;; move "bly", 0x10 into msg2
mov eax, dword[msg1+12]
mov dword[msg2+12], eax
;;; print msg1
mov eax, 4 ; write
mov ebx, 1 ; stdout
mov ecx, msg1 ; address of first message
mov edx, msg1Len ; # of chars to print
int 0x80
;;; print msg2
mov eax, 4 ; write
mov ebx, 1 ; stdout
mov ecx, msg2 ; address of second message
mov edx, msg2Len ; # of chars to print
int 0x80
;;; print msg3
mov eax, 4 ; write
mov ebx, 1 ; stdout
mov ecx, msg3 ; address of third message
mov edx, msg3Len ; # of chars to print
int 0x80
;;; exit and return to Operating System
mov ebx, 0 ; return code 0: everything Ok!
mov eax, 1
int 0x80
Problem #3
;;; ; Julia B. Edwards
;;; ; 231a-aa
;;; ; hw3c.asm (edited by D. Thiebaut)
;;; ;
;;; ; This program prints out the following:
;;; ;
;;; ; I love chocolate
;;; ; J'aime chocolat!
;;; ;
;;; ;
;;; ; by altering msg1 ("I love chocolate", 10) after it has
;;; ; been printed.
;;; ;
;;; ;
;;; ; To compile, link, and run:
;;; ; nasm -f elf -F stabs hw3c.asm
;;; ; ld -melf_i386 -o hw3c hw3c.o
;;; ; ./hw3c
;;; ;
section .data
msg1 db "I love chocolate", 10
msg1Len equ $-msg1
section .text
global _start
_start:
;;; print original string
mov eax, 4
mov ebx, 1
mov ecx, msg1
mov edx, msg1Len
int 0x80
;;; Modify the string by replacing key characters.
mov eax, "J'ai"
mov dword[msg1], eax ;change first 4 chars of msg1
mov ah, "m"
mov byte[msg1+4], ah ;change 5th char of msg1
mov ah, "!"
mov byte[msg1+msg1Len-2], ah ;change last char of msg1
;;; print modified string
mov eax, 4
mov ebx, 1
mov ecx, msg1
mov edx, msg1Len
int 0x80
;;; ; exit
mov ebx, 0
mov eax, 1
int 0x80