Difference between revisions of "CSC270 Homework 4 Solution 2012"
(Created page with "--~~~~ ---- <onlysmith> =Problem #1= No, it is not a flip-flop. It flips, but doesn't flop. When you block the NAND, you store a 1 in the flip-flop. When you block the NOR,...") |
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=Problem #1= | =Problem #1= | ||
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=Problem #2= | =Problem #2= | ||
| + | <br /><center>[[Image:CSC270Homework4Sol2012.png|500px]]</center><br /> | ||
<br /> | <br /> | ||
| + | * what happens at '''t0''': | ||
| + | ** Just before t0, D1 is 0. So after t0, Q0 is going to be 0. | ||
| + | ** Just before t0, Q0 is 0. So after t0, Q1 is going to be 0. | ||
| + | ** Just before t0, Q1 is 0. So after t0, Q2 is going to be 0. | ||
| + | * What happens at '''t1''': | ||
| + | ** Just before t1, D1 is 0. So after t0, Q0 is going to be 0. | ||
| + | ** Just before t1, Q0 is 0. So after t0, Q1 is going to be 0. | ||
| + | ** Just before t1, Q1 is 0. So after t0, Q2 is going to be 0. | ||
| + | * What happens at '''t2''': | ||
| + | ** Just before t2, D1 is 1. So after t0, Q0 is going to be 1. | ||
| + | ** Just before t2, Q0 is 0. So after t0, Q1 is going to be 0. | ||
| + | ** Just before t2, Q1 is 0. So after t0, Q2 is going to be 0. | ||
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| − | + | </onlydft> | |
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