Difference between revisions of "CSC270 Homework 5 Solution 2012"
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--[[User:Thiebaut|D. Thiebaut]] 18:24, 12 March 2012 (EDT) | --[[User:Thiebaut|D. Thiebaut]] 18:24, 12 March 2012 (EDT) | ||
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| − | < | + | <onlydft> |
=PDF= | =PDF= | ||
[[Media:CSC270Homework5Solutions2012.pdf|Pdf]] | [[Media:CSC270Homework5Solutions2012.pdf|Pdf]] | ||
=Source= | =Source= | ||
| + | |||
| + | For problem #2, since we associated Red ON with the state where Q0, Q1, and Q2 are 0, then all we need to do is clear D2, D1, and D0 when the command is 1. So we AND the functions of Problem 1 that generate D2, D1, and D0 with NOT( cmd ). No analysis necessary! | ||
<source lang="python"> | <source lang="python"> | ||
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for step in range( 20 ): | for step in range( 20 ): | ||
| − | # the Q1 and Q2 outputs go through combinational logic to generate the new values | + | # the Q0, Q1 and Q2 outputs go through combinational logic to generate the new values |
| − | # of D1, D2, and the outputs G | + | # of D1, D2, and the outputs G, R... |
D2 = NOT( Q2 ) & Q1 & NOT( Q0 ) | D2 = NOT( Q2 ) & Q1 & NOT( Q0 ) | ||
D1 = ( Q0 & Q1 ) | ( Q2 ^ Q1 ) ^ Q0 | D1 = ( Q0 & Q1 ) | ( Q2 ^ Q1 ) ^ Q0 | ||
D0 = NOT( Q2 ) & NOT( Q1 ) | ( Q2 & Q0 ) | D0 = NOT( Q2 ) & NOT( Q1 ) | ( Q2 & Q0 ) | ||
| + | |||
| + | # the outputs. Green is the opposite of Red. | ||
R = NOT( Q1 ) & NOT( Q0 ) | R = NOT( Q1 ) & NOT( Q0 ) | ||
G = NOT( R ) | G = NOT( R ) | ||
| − | # show the stable | + | # show the stable signals |
print( "Q2Q1Q0 = %d %d %d | GR = %d %d" % ( Q2, Q1, Q0, G, R ) ) | print( "Q2Q1Q0 = %d %d %d | GR = %d %d" % ( Q2, Q1, Q0, G, R ) ) | ||
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#input( "> " ) | #input( "> " ) | ||
| − | # as soon as the clock has ticked, D1 and D2 get latched in the flipflops | + | # as soon as the clock has ticked, D0, D1 and D2 get latched in the flipflops |
| − | # and Q1 and Q2 reflect the values captured. | + | # and Q0, Q1 and Q2 reflect the values captured. |
Q0 = D0 | Q0 = D0 | ||
Q1 = D1 | Q1 = D1 | ||
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for cmd in [0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,0,0,0,1,1,0]: | for cmd in [0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,0,0,0,1,1,0]: | ||
| − | # the Q1 and Q2 outputs go through combinational logic to generate the new values | + | # the Q0, Q1 and Q2 outputs go through combinational logic to generate the new values |
| − | # of D1, D2, and the outputs G | + | # of D1, D2, and the outputs G, R... |
D2 = NOT(cmd) & ( NOT( Q2 ) & Q1 & NOT( Q0 ) ) | D2 = NOT(cmd) & ( NOT( Q2 ) & Q1 & NOT( Q0 ) ) | ||
D1 = NOT(cmd) & (( Q0 & Q1 ) | ( Q2 ^ Q1 ) ^ Q0 ) | D1 = NOT(cmd) & (( Q0 & Q1 ) | ( Q2 ^ Q1 ) ^ Q0 ) | ||
D0 = NOT(cmd) & (NOT( Q2 ) & NOT( Q1 ) | ( Q2 & Q0 )) | D0 = NOT(cmd) & (NOT( Q2 ) & NOT( Q1 ) | ( Q2 & Q0 )) | ||
| + | |||
| + | # outputs. | ||
R = NOT( Q1 ) & NOT( Q0 ) | R = NOT( Q1 ) & NOT( Q0 ) | ||
G = NOT( R ) | G = NOT( R ) | ||
| − | # show the stable | + | # show the stable signals |
print( "cmd Q2Q1Q0 = %d %d %d %d | GR = %d %d" % ( cmd, Q2, Q1, Q0, G, R ) ) | print( "cmd Q2Q1Q0 = %d %d %d %d | GR = %d %d" % ( cmd, Q2, Q1, Q0, G, R ) ) | ||
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#input( "> " ) | #input( "> " ) | ||
| − | # as soon as the clock has ticked, D1 and D2 get latched in the flipflops | + | # as soon as the clock has ticked, D0, D1 and D2 get latched in the flipflops |
| − | # and Q1 and Q2 reflect the values captured. | + | # and Q0, Q1 and Q2 reflect the values captured. |
Q0 = D0 | Q0 = D0 | ||
Q1 = D1 | Q1 = D1 | ||
| Line 138: | Line 144: | ||
"""</sourcr> | """</sourcr> | ||
| − | </ | + | </onlydft> |
<br /> | <br /> | ||
