Difference between revisions of "CSC111 Homework 7 2018"
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=Solution Programs= | =Solution Programs= |
Latest revision as of 13:43, 1 June 2018
D. Thiebaut (talk) 16:06, 25 March 2018 (EDT)
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Solution Programs
Streetcar
# hw7sol.py # D. Thiebaut # This program reads a file containing a portion (or all) # of the dialogs from the play Streetcar named Desire, by # Tennessee Williams, and outputs statistics about how often # the main three characters refer to each other. def getLinesFromFile( fileName ): """Open the file whose name is passed as a parameter, and returns the lines it contains. """ return open( fileName, "r" ).readlines() def getReferences( lines, character, name ): """ Given the lines containing the dialog, the character of interest (BLANCHE, STANLEY, or STELLA), and the character they might be calling or talking about (Blanche, Stanley, or Stella), return the number of times such references occur. """ count = 0 # for each line of text for line in lines: # if STANLEY is the character, and Stella appears in his # line, increment the counter. Same for the other # characters. if line.find( character )!= -1 and line.find( name ) != -1: count = count + line.count( name ) # return the counter. return count def main(): # get the name of the file from the user. fileName = input( "File name? " ) lines = getLinesFromFile( fileName ) # get the count of the number of references by one character to # the other. StanleyCallsBlanche = getReferences( lines, "STANLEY:", "Blanche" ) StanleyCallsStella = getReferences( lines, "STANLEY:", "Stella" ) BlancheCallsStella = getReferences( lines, "BLANCHE:", "Stella" ) BlancheCallsStanley = getReferences( lines, "BLANCHE:", "Stanley" ) StellaCallsStanley = getReferences( lines, "STELLA:", "Stanley" ) StellaCallsBlanche = getReferences( lines, "STELLA:", "Blanche" ) # display the result. print( "Stanley -> Blanche = ", StanleyCallsBlanche ) print( "Stanley -> Stella = ", StanleyCallsStella ) print( "Blanche -> Stella = ", BlancheCallsStella ) print( "Blanche -> Stanley = ", BlancheCallsStanley ) print( "Stella -> Stanley = ", StellaCallsStanley ) print( "Stella -> Blanche = ", StellaCallsBlanche ) # create a list of the 6 counters and sort them in # increasing order. list = [StanleyCallsBlanche, StanleyCallsStella, BlancheCallsStella, BlancheCallsStanley, StellaCallsStanley, StellaCallsBlanche] list.sort() # The highest counter is at the end of the list most = list[-1] # display the character to references another the most, # or a special message if no references were found. if most == 0: print( "No references" ) elif StanleyCallsBlanche==most: print( "Stanley -Most-> Blanche" ) elif StanleyCallsStella==most: print( "Stanley -Most-> Stella" ) elif BlancheCallsStella==most: print( "Blanche -Most-> Stanley" ) elif BlancheCallsStanley==most: print( "Blanche -Most-> Stanley" ) elif StellaCallsStanley==most: print( "Stella -Most-> Stanley" ) elif StellaCallsBlanche==most: print( "Stella -Most-> Blanche" ) main()
Problem 2
# hw7_2.py # your names # solution program for Hw7 Problem 2. def medianOf( a, b, c ): if a <= b <= c or c <= b <= a: return b if b <= a <= c or c <= a <= b: return a return c def isInside( x, y, x1, y1, x2, y2 ): if medianOf( x, x1, x2 ) == x and medianOf( y, y1, y2 )==y: return True return False def isContained( list1, list2 ): for item in list1: if not item in list2: return False return True def makeAbsolute( list1 ): for i in range( len( list1 ) ): list1[i] = abs( list1[i] ) return list1 def numberCommonItems( list1, list2 ): count = 0 for item in list1: if item in list2: count = count + 1 return count def main(): print( medianOf( 10, 20, 15 ) ) print( medianOf( 10, 9, 5 ) ) print( isInside( 50, 50, 20, 20, 100, 200 ) ) print( isInside( 50, 50, 20, 100, 100, 30 ) ) print( isInside( 10, 10, 50, 50, 100, 100 ) ) print( isContained( ["Smith", 10, 20], ["College", 10, 30] ) ) print( isContained( [1, 10, 5], [1, 2, 5, 9, 10, 15] ) ) print( isContained( [1, 10], [1, 2, 5] ) ) print( isContained( [1, 10], [20, 100] ) ) print( makeAbsolute( [1, -10, 2, -100, 5, 7] ) ) print( numberCommonItems( [1, 2, 5], ["Smith", 5, 10, 2] ) ) print( numberCommonItems( [1, 2, 3], [4, 5] ) ) main()
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