Difference between revisions of "CSC111 Homework 6 Solution 2014"
(→Program 1) |
(→Program 2) |
||
Line 82: | Line 82: | ||
=Program 2= | =Program 2= | ||
<br /> | <br /> | ||
+ | <source lang="python"> | ||
+ | # hw6a.py | ||
+ | # Thuy Nguyen (ce) | ||
+ | # | ||
+ | # This program asks the user for an integer that will represent | ||
+ | # a chessboard with that dimension. The chessboard uses a 3x3 | ||
+ | # block to represent each cell of the board. | ||
+ | # For example, if user enters 3, this chessboard will be displayed: | ||
+ | # ###...### | ||
+ | # ###...### | ||
+ | # ###...### | ||
+ | # ...###... | ||
+ | # ...###... | ||
+ | # ...###... | ||
+ | # ###...### | ||
+ | # ###...### | ||
+ | # ###...### | ||
+ | # ----------------------------------------------------------------- | ||
+ | |||
+ | |||
+ | # Makes either black (###) or white (...) segment | ||
+ | # for each cell | ||
+ | def printBlock( visible ): | ||
+ | |||
+ | if visible==True: | ||
+ | print( "###", end="" ) | ||
+ | else: | ||
+ | print( "...", end="" ) | ||
+ | |||
+ | |||
+ | # Makes indicated number of 3x3 cell(s) and alternates | ||
+ | # black (###) and white (...) cells for each row | ||
+ | def printLine( visibility, isOdd, dimension ): | ||
+ | |||
+ | for i in range( 3 ): | ||
+ | for i in range( dimension//2 ): | ||
+ | printBlock( visibility ) | ||
+ | printBlock( not visibility ) | ||
+ | |||
+ | if isOdd: | ||
+ | printBlock( visibility ) | ||
+ | |||
+ | print() | ||
+ | |||
+ | |||
+ | # Alternates black (###) and white (...) cells the number of | ||
+ | # times that the user indicated for each column | ||
+ | def repeatLine( dimension, isOdd ): | ||
+ | |||
+ | for i in range( dimension//2 ): | ||
+ | printLine( True, isOdd, dimension ) | ||
+ | printLine( False, isOdd, dimension ) | ||
+ | |||
+ | if isOdd: | ||
+ | printLine( True, isOdd, dimension ) | ||
+ | |||
+ | |||
+ | def main(): | ||
+ | # Asks user for dimension of chessboard | ||
+ | dimension = int( Input( "Enter dimension of board: " ) ) | ||
+ | |||
+ | # Asks user again for another input | ||
+ | # if user enters negative number | ||
+ | while dimension < 0: | ||
+ | dimension = int( Input( "Invalid input. Please enter 0 or positive number: " ) ) | ||
+ | |||
+ | # Boolean variable when dimension is | ||
+ | # odd for the for loops in functions | ||
+ | isOdd = dimension % 2 == 1 | ||
+ | |||
+ | # prints chessboard | ||
+ | repeatLine( dimension, isOdd ) | ||
+ | |||
+ | |||
+ | main() | ||
+ | </source> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | <br /> | ||
+ | [[Category:CSC111]][[Category:Python]][[Category:Homework]] |
Revision as of 09:49, 26 March 2014
--D. Thiebaut (talk) 09:46, 26 March 2014 (EDT)
There were several good solution programs for Homework 6. You were not required to use a main() function, although some did. The program below is a good example of how Python programs should be organized, with a header first, possibly a few import statements, maybe a constant or two, then a long list of function definitons (def statements), then the definition of the main() function, and at the very end, one call to main() that starts the whole program.
Program 1
# Program: hw6a.py
# Programmer: Yumeng Wang(cf)
# (slightly edited by D. Thiebaut)
# The last edited time: 03/11/2014
# The program asks the user for an input which needs
# to be an integer that is greater or equal to 0,
# and then displays a chessboard with that dimension
# while each cell of the chessboard is represented by a
# 3*3 block.
# --------------------define functions---------------------
# printElement( visibility )- shows how to print one 1*3
# element in a 3*3 block.
def printElement( visibility ):
if visibility == True:
print( "###", end="" )
else:
print( "...", end="" )
# printOneLine( visibility )- print the first line of each row
def printOneLine( dimension, visibility ):
# it prints"###" and "..." one by one until
# the number of them is equal to the dimension
for i in range ( dimension ):
printElement( visibility )
visibility = not visibility
# when dimension is odd, change the visibility after
# it prints a line so that we have the original visibility
# at the beginning of every new line.
if dimension % 2 != 0:
visibility = not visibility
# printThreeLine( visibility )- print one row by print
# the same line three times.
def printThreeLine( dimension, visibility ):
for i in range (3):
printOneLine( dimension, visibility )
print()
# printBoard( visibility)- print the whole chessboard
# by printing the required number(dimension) of rows.
def printBoard( dimension, visibility ):
for i in range ( dimension ):
printThreeLine ( dimension, visibility )
visibility = not visibility
# ==================================================================
# MAIN PROGRAM
# ==================================================================
# main()- set the visibility to be true and print the
# printBoard( visibility ) function.
def main( ):
# get dimension from user
dimension = int(Input("Enter dimention of board: "))
while dimension < 0:
dimension = int(Input("Enter dimention of board: "))
printBoard( dimension, True )
main()
Program 2
# hw6a.py
# Thuy Nguyen (ce)
#
# This program asks the user for an integer that will represent
# a chessboard with that dimension. The chessboard uses a 3x3
# block to represent each cell of the board.
# For example, if user enters 3, this chessboard will be displayed:
# ###...###
# ###...###
# ###...###
# ...###...
# ...###...
# ...###...
# ###...###
# ###...###
# ###...###
# -----------------------------------------------------------------
# Makes either black (###) or white (...) segment
# for each cell
def printBlock( visible ):
if visible==True:
print( "###", end="" )
else:
print( "...", end="" )
# Makes indicated number of 3x3 cell(s) and alternates
# black (###) and white (...) cells for each row
def printLine( visibility, isOdd, dimension ):
for i in range( 3 ):
for i in range( dimension//2 ):
printBlock( visibility )
printBlock( not visibility )
if isOdd:
printBlock( visibility )
print()
# Alternates black (###) and white (...) cells the number of
# times that the user indicated for each column
def repeatLine( dimension, isOdd ):
for i in range( dimension//2 ):
printLine( True, isOdd, dimension )
printLine( False, isOdd, dimension )
if isOdd:
printLine( True, isOdd, dimension )
def main():
# Asks user for dimension of chessboard
dimension = int( Input( "Enter dimension of board: " ) )
# Asks user again for another input
# if user enters negative number
while dimension < 0:
dimension = int( Input( "Invalid input. Please enter 0 or positive number: " ) )
# Boolean variable when dimension is
# odd for the for loops in functions
isOdd = dimension % 2 == 1
# prints chessboard
repeatLine( dimension, isOdd )
main()