Difference between revisions of "CSC231 Homework 3 2014"
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* Your program should be called Hw3_3.asm, and is an extension of Hw3_2.asm. | * Your program should be called Hw3_3.asm, and is an extension of Hw3_2.asm. | ||
− | * It works the same way Hw3_2 operates, but instead of looping 20 times, the program uses a number input by the user to control the loop. | + | * It works the same way Hw3_2 operates, but instead of looping a fixed number of times, i.e. 20 times, the program uses a number input by the user ''to control the loop''. |
* Example: | * Example: | ||
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Revision as of 14:55, 29 September 2014
--D. Thiebaut (talk) 15:17, 29 September 2014 (EDT)
Contents
Preparation
Looping. Version 1
- Create the following program in your beowulf2 directory:
;;; ; loop1.asm ;;; ; D. Thiebaut ;;; ; ;;; ; a simple program using a loop in which the ecx ;;; ; register is printed. ;;; ; ;;; ; to assemble and run: ;;; ; ;;; ; nasm -f elf loop1.asm ;;; ; nasm -f elf 231Lib.asm ;;; ; ld -melf_i3896 -o loop1 loop1.o 231Lib.o ;;; ; ./loop1 ;;; ; ------------------------------------------------------------------- extern _printDec ; the function that prints eax in decimal extern _println ; the function that brings the cursor to the next line. ;;; ------------------------------------------------------------ ;;; code area ;;; ------------------------------------------------------------ section .text global _start _start: mov ecx, 10 for: mov eax, ecx call _printDec call _println loop for ;;; exit() mov eax,1 mov ebx,0 int 0x80 ; final system call
- Run it.
- Verify that it displays the different values of ecx, the loop counter.
Looping. Version 2
- This time we write the same program as the one above, but add some code to make it display "ecx = 10", "ecx = 9", etc.
- So the body of the loop will look something like this:
mov ecx, msg mov edx, MSGLEN call _printString
- You should recognize the way _printString works: you pass the address of the string in ecx, the length of the string in edx, and you call the function.
- The problem with this code is that it modifies ecx, which is our loop counter. So we'd better save ecx before we execute this code and restore it right after. We use a variable called temp for this purpose:
;;; in the data segment: temp dd 0 ; safe place to save ecx ;;; back in the code segment: mov dword[temp], ecx mov ecx, msg mov edx, MSGLEN call _printString mov ecx, dword[temp]
- Update your program with the new code, indicate that _printString is an extern function, and assemble, link, and run your new program.
- Verify that its output looks like this:
ecx = 10 ecx = 9 ecx = 8 ecx = 7 ecx = 6 ecx = 5 ecx = 4 ecx = 3 ecx = 2 ecx = 1
Looping. Version 3
- Now try this program
;;; ; loop3.asm ;;; ; D. Thiebaut ;;; ; ;;; ; a simple program using a loop in which the ecx ;;; ; register is printed. ;;; ; ;;; ; to assemble and run: ;;; ; ;;; ; nasm -f elf loop1.asm ;;; ; nasm -f elf 231Lib.asm ;;; ; ld -melf_i3896 -o loop1 loop1.o 231Lib.o ;;; ; ./loop1 ;;; ; ------------------------------------------------------------------- extern _printDec extern _println extern _printString ;;; ------------------------------------------------------------ ;;; data areas ;;; ------------------------------------------------------------ section .data Array dd 1, 10, 20, 50, 100, 150, 200, 500, 1000 ARRAYLEN equ ($-Array)/4 ; the number of dwords in Array temp dd 0 ; a place to save ecx when needed ;;; ------------------------------------------------------------ ;;; code area ;;; ------------------------------------------------------------ section .text global _start _start: mov ecx, ARRAYLEN mov ebx, Array for: ;;; display the integer at [ebx] mov eax, dword[ebx] add ebx, 4 ; make ebx point to next int in array call _printDec call _println loop for ;;; exit mov eax,1 mov ebx,0 int 0x80 ; final system call
- Read it carefully. Can you predict what it will output?
- Assemble, link, and run it.
- Verify that your intuition was correct. If it was not, make sure you understand why.
- You are now ready for the assignment.
Problem #1: warming up
- Write an assembly program called hw3_1.asm that uses a loop to print all the numbers from 1 to 20, in increasing order, one per line.
- Submit it to Moodle.
Problem #2: adding a string
- Write an assembly program called Hw3_2.asm that uses a loop to prints ecx in the following way:
1. ecx = 20 2. ecx = 19 3. ecx = 18 4. ecx = 17 ... 20. ecx = 1
- (I replaced a large number of lines using ellipses in the list above.)
Problem #3: adding an input
- Your program should be called Hw3_3.asm, and is an extension of Hw3_2.asm.
- It works the same way Hw3_2 operates, but instead of looping a fixed number of times, i.e. 20 times, the program uses a number input by the user to control the loop.
- Example:
./Hw3_3 > 4 1. ecx = 4 2. ecx = 3 3. ecx = 2 4. ecx = 1
- or, another example:
./Hw3_3 > 10 1. ecx = 10 2. ecx = 9 3. ecx = 8 4. ecx = 7 5. ecx = 6 6. ecx = 5 7. ecx = 4 8. ecx = 3 9. ecx = 2 10. ecx = 1
- In the last example, the prompt generated by the program is > followed by a space, and the user input is 10. The program then loops 10 times.
- Submit your program to Moodle.