Difference between revisions of "CSC111 Programs for Week 12 2015"
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Revision as of 18:08, 20 April 2015
--D. Thiebaut (talk) 07:11, 20 April 2015 (EDT)
Display Maze Recursively
- Here's a skeleton program to start with...
# drawChessboardRecursive.py # D. Thiebaut # A recursive way of drawing a chessboard from graphics import * WIDTH = 600 HEIGHT = 600 NOCELLS = 8 SIDE = WIDTH // NOCELLS drawnCells = [] # keep track of cells already drawn def drawCell( row, col, color, win ): """draws a square cell of the given color on the given row and column""" x1 = col * SIDE y1 = row * SIDE x2 = x1 + SIDE y2 = y1 + SIDE cell = Rectangle( Point( x1, y1 ), Point( x2, y2 ) ) cell.setFill( color ) cell.draw( win ) def opposite( color ): """return the opposite color of a given color, assuming that the opposite of white is black, and conversely""" if color=="white": return "black" else: return "white" def recursiveDraw( row, col, color, win ): """recursively draw a chessboard""" return def main(): win = GraphWin( "Chessboard", WIDTH, HEIGHT ) recursiveDraw( 0, 0, "white", win ) win.getMouse() win.close() main()
Largest, Smallest, Factorial
# Find largest item recursively. Find the smallest one, recursively.
# Compute the factorial of a number.
def findLargestR( L ):
"""given a list of numbers, returns the largest one."""
print( "findLargest(", L, ")" )
if len( L ) == 1:
print( "Stopping condition. largest =", L[0] )
return L[0]
first = L[0]
remainingL = L[1: ]
print( "first =", first, " remainingL=", remainingL )
largestOfRemainingL = findLargestR( remainingL )
print( "largest of remainingL is", largestOfRemainingL )
if first > largestOfRemainingL:
return first
else:
return largestOfRemainingL
def findSmallestR( L ):
"""given a list of numbers, returns the smallest one."""
print( "findSmallestR(", L, ")" )
if len( L ) == 1:
print( "Stopping condition. Smallest =", L[0] )
return L[0]
first = L[0]
remainingL = L[1: ]
print( "first =", first, " remainingL=", remainingL )
smallestOfRemainingL = findSmallestR( remainingL )
print( "smallest of remainingL is", smallestOfRemainingL )
if first < smallestOfRemainingL:
return first
else:
return smallestOfRemainingL
def fact( n ):
""" compute the factorial of a number."""
# stopping condition
if n == 1:
return 1
# recursive step
return n * fact( n-1 )
def main():
"""
L = [ 10, 3, 101, 23 ]
smallest = findSmallestR( L )
print( "largest = ", smallest )
"""
while True:
n = int( input( "> " ) )
print( "factorial of", n, "=", fact(n) )
main()
Recursively Visiting a Maze