Difference between revisions of "CSC231 Final Exam Fall 2017"
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| − | * Write a bash script called '''finalFact.sh''' that contains a ''recursive'' function called '''fact''' that will compute the '''factorial''' of a number passed on the command line. | + | * Write a bash script called '''finalFact.sh''' that contains a ''recursive'' function called '''fact''' that will compute the '''factorial''' of a number passed on the command line. |
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==Question == | ==Question == | ||
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| − | In the header of your program, explain the program returns 0 for fact(10). If you are not sure, suggest the most likely reason. | + | In the header of your program, explain why the program returns 0 for fact(10). If you are not sure, suggest the most likely reason. |
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==Submission== | ==Submission== | ||
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Answer the questions in the Problem 4 section of the final exam on Moodle. | Answer the questions in the Problem 4 section of the final exam on Moodle. | ||
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| − | + | =Problem 5= | |
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| + | Assume that we want to create a 16-bit floating point format similar to the IEEE floating point format we have seen in class. | ||
| + | This format uses all the rules we have studied as being intrinsic to the 32-bit format, including the ''exceptions'', and the ''biased exponent''. | ||
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| + | In this 16-bit format, the sign, exponent, and mantissa are defined as follows: | ||
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| + | * The most significant bit is the sign bit: 0 for positive, 1 for negative | ||
| + | * The next 4 bits are the exponent. The stored exponent is offset by a ''bias'' relative to the true exponent. | ||
| + | * The lower 11 bits are the mantissa, and we assume that the mantissa contains a hidden 1. All numbers, as with the 32-bit format, are normalized as 1.bbb...bbb x 2^(true exponent). | ||
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| + | ==Questions== | ||
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| + | Section 5 of the Final Exam section on Moodle contains several questions relating to this format. | ||
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=Solutions= | =Solutions= | ||
==Bash Script== | ==Bash Script== | ||
