Difference between revisions of "CSC270 Exercises on Assembly Language"

From dftwiki3
Jump to: navigation, search
(Exercise 7)
(Exercise 7)
Line 90: Line 90:
 
</source>
 
</source>
 
<br />
 
<br />
 +
=Exercise 8=
 +
* Disassemble the program below.  Its starting address is 011B:
 +
 +
011B  86
 +
011C  01 F6 00
 +
011F  1B
 +
0120  1B 97 1B 7E
 +
0124  01
 +
0125  1B
 +
 +
 
<br />
 
<br />
 
<br />
 
<br />

Revision as of 08:35, 2 April 2012

--D. Thiebaut 16:20, 27 March 2012 (EDT)


Learning Assembly Through Exercises

Exercise 1

  • Write a program that uses 3 byte variables, a, b, and c. The variable are initialized before the program starts with the values 2, 5, and 0, respectively.
  • The program will add up the contents of the variable a to that of b and store the result into c. Only c will change.

Exercise 2

  • Assemble the program of Exercise 1
  • How many bytes does it contain?
  • How fast will it go from beginning to end, assuming each 6811 cycle is 1 µsecond?

Exercise 3

  • Same as Exercise 1, but for the Pentium.
  • Assuming that the Pentium runs at a clock speed of 3 GHz, how many times could the program run on the Pentium while the same program run on the 1MHz 6811?

Exercise 4

  • We want to compute Y = a + b - c + 3, where Y, a, b, and c are byte variables.
  • Write the program that performs this operation.
  • Assemble the program
  • Count the total number of cycles it will take to run, and the total number of bytes it will use up in RAM.

Exercise 5

FibonacciRabits.png
  • Write a program that computes the first 5 terms of the fibonacci sequence, assuming that your program starts with 5 variables that all zero.
  • Assemble it.
  • How many cycles?
  • How many bytes?










Pause


6811AddressingModes.png



Exercise 6

  • Back to Exercise 4. Go through each instruction and identify the different addressing modes you used for each instruction.

Exercise 7

  • Analyze the program below and make it shorter and/or faster. Your program should compute the same result as the original program.


	org	0
 	jmp	start

a	db	0
b	db	0
c	db	0

start:  ldaa	a
	inca
        staa	a
	ldaa	b
	inca
        inca
        staa    b
        ldaa	c
	inca
        inca
        inca
        staa	c
	jmp     start


Exercise 8

  • Disassemble the program below. Its starting address is 011B:
011B  86
011C  01 F6 00
011F  1B
0120  1B 97 1B 7E
0124  01
0125  1B