Difference between revisions of "CSC231 Homework 3 Fall 2012"

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(Problem #2)
(Problem #2)
Line 35: Line 35:
 
section .data
 
section .data
 
msg1        db            "CSC231 Assembly", 10, 10
 
msg1        db            "CSC231 Assembly", 10, 10
msg1Len   equ            $-msg1
+
msg1Len     equ            $-msg1
 
msg2        db            "................", 10
 
msg2        db            "................", 10
msg2Len   equ            $-msg2
+
msg2Len     equ            $-msg2
 
msg3        db            "Fall 2012", 10, 10
 
msg3        db            "Fall 2012", 10, 10
msg3Len   equ            $-msg3
+
msg3Len     equ            $-msg3
  
 
 
Line 48: Line 48:
 
mov eax, 4 ; write
 
mov eax, 4 ; write
 
mov ebx, 1 ; stdout
 
mov ebx, 1 ; stdout
mov ecx, msg1 ; address of message to print
+
mov ecx, msg1 ; address of first message
 
mov edx, msg1Len ; # of chars to print
 
mov edx, msg1Len ; # of chars to print
 
int 0x80
 
int 0x80
Line 55: Line 55:
 
mov eax, 4 ; write
 
mov eax, 4 ; write
 
mov ebx, 1 ; stdout
 
mov ebx, 1 ; stdout
mov ecx, msg2 ; address of message to print
+
mov ecx, msg2 ; address of second message
 
mov edx, msg2Len ; # of chars to print
 
mov edx, msg2Len ; # of chars to print
 
int 0x80
 
int 0x80
Line 62: Line 62:
 
mov eax, 4 ; write
 
mov eax, 4 ; write
 
mov ebx, 1 ; stdout
 
mov ebx, 1 ; stdout
mov ecx, msg3 ; address of message to print
+
mov ecx, msg3 ; address of third message
 
mov edx, msg3Len ; # of chars to print
 
mov edx, msg3Len ; # of chars to print
 
int 0x80
 
int 0x80

Revision as of 13:01, 19 September 2012

--D. Thiebaut 13:51, 19 September 2012 (EDT)


This homework can be done in pair. It is due at 11:59 p.m. + 1 min on 9/26/12 (which might be Mountain Day...)


Problem #1

What is left in eax, ebx, ecx, and edx after the following instructions have executed. Express your answer in hexadecimal.

mov eax, 0x0
mov ebx, 0x12345678
mov ecx, 0x87654321
mov edx, 0xffffffff

mov al, bl
mov ah, ch
mov dl, dh
mov dh, bl
mov bx, cx
mov cx, 0

;;; show what is in eax, ebx, ecx, and edx now.

Problem #2

Starting with the program listed below, complement it so that it moves the string msg1 into msg2 and displays all three strings on the screen.


		section	.data
msg1        db             "CSC231 Assembly", 10, 10
msg1Len     equ            $-msg1
msg2        db             "................", 10
msg2Len     equ            $-msg2
msg3        db             "Fall 2012", 10, 10
msg3Len     equ            $-msg3

	
		section	.text
		global	_start
_start:	
;;; print msg1
		mov	eax, 4		; write
		mov	ebx, 1		; stdout
		mov	ecx, msg1	; address of first message
		mov	edx, msg1Len	; # of chars to print
		int 	0x80

;;; print msg2
		mov	eax, 4		; write
		mov	ebx, 1		; stdout
		mov	ecx, msg2	; address of second message
		mov	edx, msg2Len	; # of chars to print
		int 	0x80

;;; print msg3
		mov	eax, 4		; write
		mov	ebx, 1		; stdout
		mov	ecx, msg3	; address of third message
		mov	edx, msg3Len	; # of chars to print
		int 	0x80

;;; exit
		mov	ebx, 0
		mov	eax, 1
		int	0x80


The original program outputs:

CSC231 Assembly

................
Fall 2012

Your assignment is to add a series of instructions before the first section that prints msg1 that will copy msg1 into msg2, as efficiently as possible, and without using loops, so that the program will print:

CSC231 Assembly

CSC231 Assembly

Fall 2012


Note: you cannot modify the way msg1, msg2, or msg3 are defined in your program. Typically you will copy-paste the program above into a new file called hw3b.asm and add a new series of instructions at the beginning of the code section.

Problem #2