CSC231 Exercises with conditinal jumps Solutions

Exercises on Conditional Jumps

Finding the minimum

Find the minimum of 3 signed int variables a, b, and c

	section	.data
a       dd      3
b       dd      5
c       dd      1        
min     dd      0
        
	section	.text
	global	_start

_start:

;;; if a <= b:           # if1
;;;     if a <= c:       # if2
;;;         min = a      # 
;;;     else: # a > c    # else2
;;;         min = c      
;;; else: # a > b        # else1
;;;     if b >= c:       # if3
;;;         min = c
;;;     else: # b < c    # else3
;;;         min = b

        mov     eax, dword[a]
        mov     ebx, dword[b]
        mov     ecx, dword[c]
        
if1:    cmp     eax, ebx
        jg      else1
if2     cmp     eax, ecx
        jg      else2
        mov     dword[min], eax
        jmp     done
else2:  mov     dword[min], ecx
        jmp     done
else1:
if3:    cmp     ebx, ecx
        jl      else3
        mov     dword[min], ecx
        jmp     done
else3:  mov     dword[min], ebx
done:
        

Loop until overflow

Print fibonacci numbers coded as unsigned words until the result overflows. Don't print erroneous numbers!

3 Solution programs:

• FibOverflowByte.asm: using an array of bytes
• FibOverflowWord.asm: using an array of words
• FibOverflowDWord.asm: using an array of dwords

All 3 require

• driver.c
• asm_io.inc
• asm_io.asm

Scanning an array

Find the largest element of a 1-dimensional array of signed double-words.

Same question, but with unsigned double words.

Characters and lower/upper case conversion

The program makeUpper.asm transforms all characters in a string to uppercase, but will also transform other characters that are not letters.

Modify the program so that it modifies only characters between 'a' and 'z' included.

Long/short jumps

Conditional jumps can jump only +127 bytes down, -128 bytes up in the code. How can we code something like this:

                 cmp     eax,10
                 jl      there
                 ...
                 ...
        there:   ...

when the instruction at Label there is 1000 bytes away from the jl conditional jump?

Print 2-dimensional arrays

Write the code necessary for printing an array of chars (maze) using for-loops depending on i and j indexes.

;;;  ------------------------------------------------------------
;;;  data areas
;;;  ------------------------------------------------------------

        section .data
maze    db "################################"     
maze2   db "            #  #           #    "     
        db "#########   #  #  #######  #   #"
        db "#           #  #        #      #"
        db "#########         ##############"
        db "#           ####               #"
        db "################################"
C       equ maze2-maze  ; num of columns
R       equ 7           ; num of rows

i        dd          0
j        dd          0