Difference between revisions of "CSC212 Homework 4 2014"
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=Problem #1= | =Problem #1= | ||
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− | Write a program that computes the result of an arithmetic expression written in ''reverse polish notation'' (RPN), also called '''postfix notation''' | + | Write a program that computes the result of an arithmetic expression written in ''reverse polish notation'' (RPN), also called '''postfix notation'''. We use '''post'''fix to indicate that the operator appears after (post) the operands. You may want to read this [http://www-stone.ch.cam.ac.uk/documentation/rrf/rpn.html page] introducing the concept. |
− | A regular, error-free, | + | We, as humans, are used to ''infix'' notation. In the infix notation, the operators appear in between the operands. For example 3 + 5. A regular, error-free, infix expression can be transformed into its postfix exquivalent easily, as illustrated with a few examples: |
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Revision as of 16:03, 1 October 2014
--D. Thiebaut (talk) 15:49, 1 October 2014 (EDT)
Problem #1
Write a program that computes the result of an arithmetic expression written in reverse polish notation (RPN), also called postfix notation. We use postfix to indicate that the operator appears after (post) the operands. You may want to read this page introducing the concept.
We, as humans, are used to infix notation. In the infix notation, the operators appear in between the operands. For example 3 + 5. A regular, error-free, infix expression can be transformed into its postfix exquivalent easily, as illustrated with a few examples:
regular expression | RPN expression |
---|---|
3 + 5 |
3 5 + |
3 * ( 5 - 2 ) |
3 5 2 - * |
(4 -1 ) * 8 |
4 1 - 8 * |
( 5 * 10 ) / ( 3 - 2 ) |
5 10 * 3 2 - / |
RPN expressions can be solved very easily by using a stack. For example, if the expression is:
3 5 + 7 *
which corresponds to (3 + 5) * 7, we proceed as follows: we read the symbols (numbers and operators) one at a time from the input, and if we find a number, we push it in the stack. If we find an operator, we pop 2 numbers from the stack, one after the other, apply the operator to the two numbers, then push the result back in the stack.
- Example
- Assume we want to evaluate the postfix string "3 5 + 6 *". Its infix equivalent to (3 + 5 ) * 6, which is 48.
Here we go: we scan our string, and get each number, or operator, one at a time.
3 --> push it in the stack: stack = [3] 5 --> push it in the stack: stack = [5 3] (the top of the stack is 5) + --> Operator! we pop the stack, get 5, pop again, get 3, add 5+3 together, 8, push that back in the stack. stack = [8] 6 --> push it in the stack: stack = [6 8] * --> Operator! we pop the stack, get 6, pop again, get 8, multiply 6 by 8 ,48, push that back in the stack. stack = [48] Done! the result is at the top of the stack.
- You may want to watch this video for an additional example:
Your assignment
- Write a program that reads postfix expressions from the input (there may be several lines of input), and for each one prints out the result.
- The numbers will always be integers
- The operators may be +, -, * or /. 10 2 / results in 5. 10 2 - results in 8.
- Call your program Hw4_1.java, and submit it to Moodle.
- You can assume for this problem that the expressions will always be error free.
Testing information
- You may want to put several expressions in a text file, say, expressions.txt, and test your program this way:
javac Hw4_1.java java Hw4_1 < expressions.txt
- Some expressions and their results:
Postfix expression | Result |
---|---|
3 5 + |
8 |
3 5 + 7 + |
15 |
2 8 + 3 11 + * |
140 |
1 2 3 4 + + + |
10 |