CSC231 Homework 7 Solution 2010
--D. Thiebaut 15:04, 19 November 2010 (UTC)
Part 1
hw7.txt
RB Axtell and Amy Tayloe (Edited by D.T.)
231a-af 231a-ai
10/11/2010
1) It would print ecx lines. The code has ecx as 0 so it will loop 4 billion times.
0 decrements to -1 which in unsigned format is FFFF FFFF. The value after that
will be FFFF FFFE, and so on, down to 0.
2) Each time through the loop 4 bytes are added the stack. If the stack has 1000 bytes,
after 251 (1000/4 + 1) lines of "hello world" are printed a segmentation fault will be
thrown before the data section is overwritten. It will not run to completion (256 lines printed),
but will stop 5 lines short of the end.
3) If standard error is sent to the same paper, the words "Segmentation fault" will be printed
after 251 lines. Otherwise, there will be no evidence of the bug without counting the number
of lines.
4) A quarter of the stack plus 1 or 256 if the stack is big enough (1024 bytes).
Part 2
;;; hw7.asm
;;; Amy Tayloe, 231a-ai
;;; Last modified 11/10/10
;;;
;;; Program that takes an unsigned, 32-bit integer and prints it out.
;;; Assumes integer (held in x) is in decimal form.
;;; Uses the stack and at least one function.
;;; Sample output:
;;; 1234589
;;;
;;; to assemble and run:
;;;
;;; nasm -f elf -F stabs hw7.asm
;;; ld -melf_i386 -o hw7 hw7.o
;;; ./hw7
;;; -------------------------------------------------------------------
;%include files here...
EXIT equ 1
WRITE equ 4
STDOUT equ 1
;; ------------------------------------------------------------
;; Data Area
;; ------------------------------------------------------------
section .data
;;; Variable to print
x dd 1234589
;;; Array to hold the decimal values of x
arrx dd 0,0,0,0,0,0,0,0,0,0
;;; Place in memory to hold ascii value of integer to be printed
temp dd 0
nl dd 10
;; ------------------------------------------------------------
;; Code Area
;; ------------------------------------------------------------
section .text
global _start
_start:
;;; Master function
call getDecimal
mov eax, arrx
;;; Loops N times, where N is the number of integers
mov ecx, 10
.for:
push eax
call moveTemp
call printTemp
;;; Increments eax by 4 to go to the next value
add eax, 4
loop .for
call printNL
;;; call printNL
;; exit()
theEnd:
mov eax,EXIT
mov ebx,0
int 0x80 ; final system call
;;; Function to put the decimal values of the integer in x onto the stack
;;; Assumes nothing on the stack
getDecimal:
pushad
;;; Loop 10 times (held in nl)
mov ecx, [nl]
dec ecx
.for:
;;; Put the integer into eax, to be divided
mov edx, 0
mov eax, [x]
mov ebx, 10
div ebx
;;; Replace previous value with quotient
mov [x], eax
;;; Push the remainder into the array
mov ebx, arrx
add ebx, ecx
add ebx, ecx
add ebx, ecx
add ebx, ecx
mov [ebx], edx
loop .for
popad
ret
;;; Funtion to put the ascii value of a given integer into temp
;;; Assumes the location of the integer is on the stack
moveTemp:
push ebp
mov ebp, esp
pushad
;;; Move the location of the integer into ebx
mov ebx, [ebp+8]
;;; Move the integer into eax
mov eax, [ebx]
;;; Increments the value by 48 (the ascii decimal value of 0)
add eax, 48
;;; Put that value into temp
mov [temp], eax
popad
pop ebp
ret 1*4
;;; Function to print the word held at temp
;;; Assumes nothing on the stack
printTemp:
pushad
mov eax, WRITE
mov ebx, STDOUT
mov ecx, temp
mov edx, 4
int 0x80
popad
ret
;;; Function to print a new line, to look nice
;;; Assumes nothing on the stack
printNL:
pushad
mov eax, WRITE
mov ebx, STDOUT
mov ecx, nl
mov edx, 4
int 0x80
popad
ret