CSC270 Homework 10
--D. Thiebaut 18:51, 14 April 2009 (UTC)
Problem #1
With the design we have been using in the last 2 labs, we use a 4-to-10 decoder which decodes E, A15, A14, and A13 and activates a signal when the processor accesses memory at an address starting by 8XXX or 9XXX.
The advantage of this method is that it is very economical in circuitry. Its problem, though, is that we can only use 8