Difference between revisions of "CSC111 Lab 10 2014"

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(Part 2: A List of Dogs)
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==Part 2: A List of Dogs==
 
==Part 2: A List of Dogs==
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* Using the '''Person''' class as an example, create a new class that will be called '''Dog''' that will contain the information relative to a dog.  We will assume that we need to keep track of the following information for each dog:
 
* Using the '''Person''' class as an example, create a new class that will be called '''Dog''' that will contain the information relative to a dog.  We will assume that we need to keep track of the following information for each dog:

Revision as of 21:50, 7 April 2014

--D. Thiebaut (talk) 13:39, 7 April 2014 (EDT)



This lab presents some exercises on


Exceptions


If you feel you have a good handle on exceptions, then move on to the next section. Otherwise do the exercises of this section.

TypeError Exceptions


The code section below will be our testbed for this part of the lab. You have to make it compute the different values we are interested in without using if/else/elif statements, using instead try/except statements.



# happiness.py
# Lab 10 demo

SWsFriends = [
    # name    pocket-money  debt
    ("Sleepy",  10,         "NA" ),
    ("Sneezy",  25.50,      0 ),
    ("Bashful", 0.50,       10.51 ),
    ( "Happy",  0,          0 ),
    ( "Grumpy", 0,          100.30 ),
    ( "Dopey",  "NA",       0 ),
    ( "Doc",    200,        0 ) ]

def main():
    for name, pocket, debt in SWsFriends:
        print( name, "has", pocket, "dollar(s) in his pocket, and owes",
                debt, "dollar(s)" )

main()



  • Run the program.
  • Notice that some amounts of money have "NA" as a value (Not Available).
  • Add a for-loop to your program that will add up the total amount of money Snow White's friends have in their pocket.

Do not anticipate errors. Just go for it! Assume there won't be errors and put all the code necessary to compute the sum of all the numbers in the 2nd column.

  • When you run your program the first time, you will get a TypeError because you cannot take the float( ) of the string "NA". Add a try/except clause around the addition, as illustrated below:


    try:
        sumPocket += pocket
    except TypeError:
        continue


  • Run your program again. Verify that you get the total sum in all the pockets (we assume that NA will be equivalent to 0).
total sum in all the pockets:  236.0


Challenge 1

QuestionMark1.jpg


  • Add a new loop that computes the total amount of debts held by the 7 friends.
  • Do not use if statements. Use a new try/except clause to protect your code from exceptions.






Challenge 2

QuestionMark3.jpg


  • Make your program print the contents of the list in 3 columns, as shown below:


Sleepy             10         NA
Sneezy           25.5          0
Bashful           0.5      10.51
Happy               0          0
Grumpy              0      100.3
Dopey              NA          0
Doc               200          0



Printing an Error Message for the User


When you catch an exception, the catch TypeError type of statement indicates some like "if there is an exception of type TypeError, then... But that does there is actually an object of type TypeError, an we can ask Python to give it to us, if we want to. The way to do this is to write:


 except TypeError as err:
     ...


in this case, err is the object of type TypeError. Most objects of this type have a member variable called args, which is a list of arguments, and which includes the description of the error in the first location. So to print it, one would simply do this:

 except TypeError as err:
        print( err.args[0] )


The full program would look something like this:

SWsFriends = [
    # name    pocket-money  debt
    ("Sleepy",  10,         "NA" ),
    ("Sneezy",  25.50,      0 ),
    ("Bashful", 0.50,       10.51 ),
    ( "Happy",  0,          0 ),
    ( "Grumpy", 0,          100.30 ),
    ( "Dopey",  "NA",       0 ),
    ( "Doc",    200,        0 ) ]


sumPocket = 0
for name, pocket, debt in SWsFriends:
    try:
        sumPocket += pocket
    except TypeError as err:
        print( err.args[0] )
        continue

print( "total sum in all pockets: ", sumPocket )



Challenge 3

QuestionMark3.jpg


  • Update your program and make it print the exception string whenever an exception occurs.








Object Oriented Programming (OOP)


Part 1



Challenge 4

QuestionMark4.jpg


  • Modify the program and make it ask the user for the information about a new student, and add this student to the list. Print the list at the end.








Challenge 5

QuestionMark5.jpg


  • Play with this code in the console:
>>> L = [30, 50, 20, 10, 100]
>>> L.pop( 2 ) 
>>> L

  • Once you figured out how pop() works on a list, make your program ask for a student name, and then remove that student from the list.







Part 2: A List of Dogs

DogCartoon.jpg


  • Using the Person class as an example, create a new class that will be called Dog that will contain the information relative to a dog. We will assume that we need to keep track of the following information for each dog:
    • tag name (string)
    • age (int)
    • vaccinated (boolean)
    • breed (string)


  • Add a dog to the list using the simplest way, illustrated below:


    dogs.append(  Dog( "Rex", 4, True, "German Sheperd" ) )


  • Make your program display the list of dogs
  • When this works, add three more dogs to the list. Make some of them vaccinated, some not vaccinated. Make sure the program displays the list correctly.